If n=2, you can address 2 locations (0, 1, 2, and 3). As you can see, number of addressable locations = n^2. This means that n=log(1024) to the base 2. Thus, n=10.

It means that a memory of 2048 words, where each word is 4 bits. So to address 2048 (or 2K, where K means 2^10 or 1024), you need 11 bits, so 11 address lines.

For a memory of size N, you’ll need log(2)N address bits. So, if N = 4096, you’ll need 12 address bits.

“20” address lines or address bus are required to span “1MB” memory space. Because 1MB is equal to bytes.

3 Answers. One address addresses one byte. Using 16 bits, you can write 65536 addresses (from 0 to 65535, that’s 65536 different addresses), and address 65536 bytes. 65536 bytes is 64kB.

2 Answers. To express in very easy terms, without any bus-multiplexing, the number of bits required to address a memory is the number of lines (address or data) required to access that memory. Quoting from the Wikipedia article, a system with a 32-bit address bus can address 232 (4,294,967,296) memory locations.

An 8-bit color system is capable of producing over 16 million colors. What is more shocking is that a 12-bit system is able to produce a whopping 4096 x 4096 x 4096 = 68,719,476,736 colors! As a result, increasing the color depth will enable you to better represent your colors.

COMPARISON

A display system that provides 4,096 shades of color for each red, green and blue subpixel for a total of 68 billion colors. For example, Dolby Vision supports 12-bit color.

Bits vs Bits per channel So, a standard color image that we commonly call “8-bit” actually can fit well more than just 256 shades. It’s more accurate to call it an 8-bit per channel image.

The colour depth of an image is measured in bits . The number of bits indicates how many colours are available for each pixel. In the black and white image, only two colours are needed. This means it has a colour depth of 1 bit….Colour depth.